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cody331 · 12-11-2008, 12:54 AM

Well since finals are next week i need to start bucklin down on my chemistry work and some of this shit i dont know, so im here to ask you guys if you could help me

I need a good/easy explaination on how you got the answer please

5.Find The number of moles in each of the number of represenentative particles.
b. 3.87 x 10^21 molecules of ALF3

6.How many representative particles are in each of the following mole quanities?
b. 4.20 x10-3(Think thats 10^3 not sure what that is) mol K2S

7. Convert the following two-step quantities, converting first to the mole and then to the desired quantity
A. Find the number of molecules in 60.0 g of N20

How many representative particles, remember that means molecules for compounds or atoms for elements, are there in 0.50 moles of H20?

What is the mass in grams of 3.0 x 10^3 mles of N2?

**And last one i get, but i dont get it**

What is the metallic ion in the compound NaCL?
(Neither one is metallic?!?!)

MrWafflez · 12-11-2008, 01:00 AM

5. ( 3.87 x 10^21 ) / (6.02 x 10^23)

6. ( 4.20 x 10^3 ) x (6.02 x 10^23)

7. 60 g N2O X ( 1 mol N2O / (2( Molar mass of N ) + ( Molar mass of O ) ))

Ans x ( 6.02 x 10^23 )

To find particles from a mass you first find moles by dividing the mass you have by the sum of molar masses in the compound. So O2 would be 16 + 16, or 32. Then you multiply by the number of particles in one mole, 6.02 x 10^23.

Na is a metal, so sure, go with that.

cody331 · 12-11-2008, 01:18 AM

like how you have ( 3.87 x 10^21 ) / (6.02 x 10^23) is that how i would put it in the calculator to solve it? Parenthesis and all?

MrWafflez · 12-11-2008, 02:12 AM

Yes, a calculator might mess up without the parentheses because you have two terms, but it should work with or without.

All those problems only deal with one concept, which is what a mole is.

6.02 x 10^23.

Simple as that.

Xkarinx · 12-11-2008, 02:13 AM

lol im doing this too in chem right now, its quite easy once u get the term in moles then from mole to w/e u need to get it into.

Cereal&Milk · 12-11-2008, 02:23 AM

2nd year of Chem and this concept still doesn't stick. I doubt it'll stick in my 3rd year, either. :X

Xkarinx · 12-11-2008, 02:26 AM

Quote:

Originally Posted by Cereal&Milk

2nd year of Chem and this concept still doesn't stick. I doubt it'll stick in my 3rd year, either. :X

you going chem major?

Cereal&Milk · 12-11-2008, 02:28 AM

No, but it's a requirement at my school. I'd rather not take the class because I have the memory and attention span of a baby cockroach. The other choice would be Biology, though, and that's worse than just learning a few concepts. :x

Xkarinx · 12-11-2008, 02:31 AM

Quote:

Originally Posted by Cereal&Milk

No, but it's a requirement at my school. I'd rather not take the class because I have the memory and attention span of a baby cockroach. The other choice would be Biology, though, and that's worse than just learning a few concepts. :x

Next year i wanna take psychology

Cereal&Milk · 12-11-2008, 02:43 AM

Taking that now, lol. It would probably be best to stop derailing the topic, though.

12-11-2008, 12:54 AM	#1 (permalink)
cody331 Diddy Kong's Boxers Join Date: Sep 2007 Posts: 670 Reputation: 29	Chemistry Help Please? Well since finals are next week i need to start bucklin down on my chemistry work and some of this shit i dont know, so im here to ask you guys if you could help me I need a good/easy explaination on how you got the answer please 5.Find The number of moles in each of the number of represenentative particles. b. 3.87 x 10^21 molecules of ALF3 6.How many representative particles are in each of the following mole quanities? b. 4.20 x10-3(Think thats 10^3 not sure what that is) mol K2S 7. Convert the following two-step quantities, converting first to the mole and then to the desired quantity A. Find the number of molecules in 60.0 g of N20 How many representative particles, remember that means molecules for compounds or atoms for elements, are there in 0.50 moles of H20? What is the mass in grams of 3.0 x 10^3 mles of N2? And last one i get, but i dont get it What is the metallic ion in the compound NaCL? (Neither one is metallic?!?!)

12-11-2008, 01:00 AM	#2 (permalink)
MrWafflez Str1der's Stooge Join Date: May 2006 Posts: 3,261 Reputation: 71	5. ( 3.87 x 10^21 ) / (6.02 x 10^23) 6. ( 4.20 x 10^3 ) x (6.02 x 10^23) 7. 60 g N2O X ( 1 mol N2O / (2( Molar mass of N ) + ( Molar mass of O ) )) Ans x ( 6.02 x 10^23 ) To find particles from a mass you first find moles by dividing the mass you have by the sum of molar masses in the compound. So O2 would be 16 + 16, or 32. Then you multiply by the number of particles in one mole, 6.02 x 10^23. Na is a metal, so sure, go with that. __________________ Last edited by MrWafflez; 12-11-2008 at 01:03 AM.

12-11-2008, 02:12 AM	#4 (permalink)
MrWafflez Str1der's Stooge Join Date: May 2006 Posts: 3,261 Reputation: 71	Yes, a calculator might mess up without the parentheses because you have two terms, but it should work with or without. All those problems only deal with one concept, which is what a mole is. 6.02 x 10^23. Simple as that. __________________

12-11-2008, 02:23 AM	#6 (permalink)
Cereal&Milk OnRPG Elite Member! Join Date: Jan 2007 Posts: 11,669 Reputation: 82	2nd year of Chem and this concept still doesn't stick. I doubt it'll stick in my 3rd year, either. :X __________________ Currently Playing: Final Fantasy 11 Server: Caitsith *~Mains~* Stats: SAM 75/ THF 37 Stats: THF 75/ NIN 37 Stats: RNG 75/ SAM 37 Stats: BLU 66/ NIN 33

12-11-2008, 02:28 AM	#8 (permalink)
Cereal&Milk OnRPG Elite Member! Join Date: Jan 2007 Posts: 11,669 Reputation: 82	No, but it's a requirement at my school. I'd rather not take the class because I have the memory and attention span of a baby cockroach. The other choice would be Biology, though, and that's worse than just learning a few concepts. :x __________________ Currently Playing: Final Fantasy 11 Server: Caitsith *~Mains~* Stats: SAM 75/ THF 37 Stats: THF 75/ NIN 37 Stats: RNG 75/ SAM 37 Stats: BLU 66/ NIN 33

12-11-2008, 01:18 AM	#3 (permalink)
cody331 Diddy Kong's Boxers Join Date: Sep 2007 Posts: 670 Reputation: 29	like how you have ( 3.87 x 10^21 ) / (6.02 x 10^23) is that how i would put it in the calculator to solve it? Parenthesis and all?

12-11-2008, 02:13 AM	#5 (permalink)
Xkarinx Banned Join Date: Dec 2008 Posts: 387 Reputation: 9	lol im doing this too in chem right now, its quite easy once u get the term in moles then from mole to w/e u need to get it into.

12-11-2008, 02:43 AM	#10 (permalink)
Cereal&Milk OnRPG Elite Member! Join Date: Jan 2007 Posts: 11,669 Reputation: 82	Taking that now, lol. It would probably be best to stop derailing the topic, though. __________________ Currently Playing: Final Fantasy 11 Server: Caitsith *~Mains~* Stats: SAM 75/ THF 37 Stats: THF 75/ NIN 37 Stats: RNG 75/ SAM 37 Stats: BLU 66/ NIN 33

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