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#1 (permalink) |
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Murxidon's Maid
Join Date: Jan 2007
Location: Auckland, New Zealand
Posts: 2,125
Reputation: 74
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I've been trying to figure this out for about an hour.. but to no avail.
In words: Three boys ran in a race. Their total time was 24 minutes. Bill ran 3 minutes quicker than Peter. Michael ran 3 times quicker than Bill. Find the race times of each boy. tl;dr: x + 3 = y y * 3 = z x + y + z = 24 From what I've gotten: x + (x+3) + 3 (x+3) = 24 5x + 12 = 24 x = 12 / 5 y = 12 / 5 + 3 y = 27 / 5 z = y x 3 z = 81/5 Therefore x = 2.4 y = 5.4 z = 16.2 Is this right? I've asked several people, but they've gotten different answers. inb4doyourhomeworkyourself Thanks. |
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#2 (permalink) | |
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Théoden, King of Rohan
Join Date: May 2006
Location: The Realm of Rohan
Posts: 7,678
Reputation: 186
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Quote:
THREAD LOCKED CAUSE WOSHII IS A B!TCH. how could you, woshii, how could you...
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Last edited by power_gamer_6; 04-08-2010 at 04:42 AM. |
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#4 (permalink) | |
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Power_Gamer_6's Pick
Join Date: Apr 2007
Location: Smoothville
Posts: 2,447
Reputation: 232
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Quote:
I saw that too. I am disappoint. |
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#5 (permalink) |
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Roon's Rogue
Join Date: Oct 2008
Location: The Pond
Posts: 4,270
Reputation: 260
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B, p, m
b=p-3 (bill ran 3 mins faster than peter, so peter's time minus 3 equals bill's time) -->p=b+3 (solve for p) m=b/3 (michael was 3 times quicker than bill, so if you take bill's time and divide it by 3 you get michael's) b+p+m=24 (the three equal 24) b+(b+3)+(b/3)=24 (solve for b) 3b/3 + (3b+9)/3 + b/3 = 72/3 (find common denominator) (4b + 3b + 9)/3 = 72/3 (combine) 7b+9=72 (multiply both sides by 3 to get rid of fraction) 7b=63 b=9 m=3 p=12 b+m+p = 24 Last edited by Paladuck; 04-08-2010 at 07:02 AM. |
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#6 (permalink) | |
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OnRPG Elite Member!
Join Date: Jul 2007
Posts: 8,049
Reputation: 138
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#10 (permalink) | |
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Feedbacker
Join Date: May 2006
Location: The Middle of the Stairs
Posts: 13,389
Reputation: 126
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Quote:
Or your could reverse the first equation as well. ezpz.
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