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Jakuza · 05-20-2008, 02:57 AM

Seriously, I feel very stupid. I've been stressing over five problems for the past three hours. I even tried googling the topics and notes but nothing seems to help.

So the topic is Rational Expressions, I have to solve them.

All I need is one-two prime examples and then I can finally do the last few.

1/c + 1/3c = 2/3

&

y squared - 2 / y squared - 16 = y - 2 / y - 4

Any help is appreciated and will lessen the stress.

Math isn't my strong point...

Runahs · 05-20-2008, 02:58 AM

Is this being graded? If not just write shit down.

Other then that I have no idea since I'm in middle school.

Kn7ghT · 05-20-2008, 03:00 AM

Last time I had a problem I couldn't solve I used my penis to puncture a hole in the paper where the problem was.

Therefore destroying the problem.

I showed my male superiority.

(thread has been destroyed by kn7ght)

Piggy-Bank · 05-20-2008, 03:23 AM

Kn7ght. You're hilarious mister. No more out of you tonight or I'll have to punish you.

Jakuza, I'm not in Algebra at the moment so I've yet to learn this. However, I just used some logical thinking and figured out the first one. I'm currently doing the second one, and if I figure it out I'll be sure to give you the answer. Anyway, here is how I did the first one.

Starting problem:

1/C + 1/3C = 2/3
1/C(1/1 + 1/3) = 2/3 Factor out the 1/C (Distributive Property)
(1/1 + 1/3) = 2C/3 Multiply both sides by 'C' to try and isolate 'C'.
3(1/1 + 1/3) = 2C Multiply both sides by '3'
3/1 + 3/3 = 2C Distributive property to simplify
3 + 1 = 2C Simplify
4 = 2C Simplify
2 = C Isolate 'C'

I'll try and get the other one later. Hope I've helped.

ARandomGuy · 05-20-2008, 03:24 AM

((y^2)-2)/((y^2)-16)=(y-2)/(y-4)

Factor the (y^2)-16 into (y-4)(y+4), then cancel the y+4 with the other y+4 on the other side of the equation. Cross multiply to get:

(y+4)(y-2)=(y^2)-2

Multiply the (y+4)(y-2) to get ((y^2)+2y-8)=(y^2)-2

The two y^2 cancels each other out.

2y-8=-2, add the 8 on to the other side to get: 2y=6, divide by 2, y=3

PugsPwn · 05-20-2008, 03:26 AM

Quote:

Originally Posted by ARandomGuy

((y^2)-2)/((y^2)-16)=(y-2)/(y-4)

Factor the (y^2)-16 into (y-4)(y+4), then cancel the y+4 with the other y+4 on the other side of the equation. Cross multiply to get:

(y+4)(y-2)=(y^2)-2

Multiply the (y+4)(y-2) to get ((y^2)+2y-8)=(y^2)-2

The two y^2 cancels each other out.

2y-8=-2, add the 8 on to the other side to get: 2y=6, divide by 2, y=3

LOL WRONG owned!

Piggy-Bank · 05-20-2008, 03:27 AM

Dang. I was too slow. I also got the second one. Ask if you need me to explain it.

@PugsPwn: What are you talking about? The answer is correct. Plug it into the equation again and you'll end up with -7/7 = -1/1

Glavus · 05-20-2008, 03:28 AM

Lets see who comes out as a smart person, the winner gets to help me with homework for a month. Is this seriously gonna be checked though? My teach never check what I actually do.

Jakuza · 05-20-2008, 03:29 AM

Oh, you guys are good. Let me write this down and take time to process it through this brain of mine.

PugsPwn · 05-20-2008, 03:30 AM

Quote:

Originally Posted by Piggy-Bank

Dang. I was too slow. I also got the second one. Ask if you need me to explain it.

@PugsPwn: What are you talking about? The answer is correct. Plug it into the equation again and you'll end up with -7/7 = -1/1

Oh yeah sorry @_@

05-20-2008, 02:57 AM	#1 (permalink)
Jakuza OnRPG Elite Member! Join Date: May 2006 Location: Flower City, NY. Posts: 10,737 Reputation: 152	Stress over math problems for the last 3 hours. Seriously, I feel very stupid. I've been stressing over five problems for the past three hours. I even tried googling the topics and notes but nothing seems to help. So the topic is Rational Expressions, I have to solve them. All I need is one-two prime examples and then I can finally do the last few. 1/c + 1/3c = 2/3 & y squared - 2 / y squared - 16 = y - 2 / y - 4 Any help is appreciated and will lessen the stress. Math isn't my strong point... __________________

05-20-2008, 02:58 AM	#2 (permalink)
Runahs Power_Gamer_6's Pick Join Date: Dec 2006 Location: amazonia Posts: 2,355 Reputation: 77	Is this being graded? If not just write shit down. Other then that I have no idea since I'm in middle school. __________________

05-20-2008, 03:00 AM	#3 (permalink)
Kn7ghT Banned Join Date: Aug 2006 Location: Soviet Union Posts: 2,213 Reputation: 34	Last time I had a problem I couldn't solve I used my penis to puncture a hole in the paper where the problem was. Therefore destroying the problem. I showed my male superiority. (thread has been destroyed by kn7ght) Last edited by Kn7ghT; 05-20-2008 at 03:14 AM.

05-20-2008, 03:28 AM	#8 (permalink)
Glavus Phantom's Freak Join Date: May 2006 Location: No Idea. Posts: 2,592 Reputation: 38	Lets see who comes out as a smart person, the winner gets to help me with homework for a month. Is this seriously gonna be checked though? My teach never check what I actually do. __________________ A little browser MMO

05-20-2008, 03:29 AM	#9 (permalink)
Jakuza OnRPG Elite Member! Join Date: May 2006 Location: Flower City, NY. Posts: 10,737 Reputation: 152	Oh, you guys are good. Let me write this down and take time to process it through this brain of mine. __________________

05-20-2008, 03:23 AM	#4 (permalink)
Piggy-Bank Norrin Radd's Nerd Rage Join Date: May 2006 Posts: 1,615 Reputation: 30	Kn7ght. You're hilarious mister. No more out of you tonight or I'll have to punish you. Jakuza, I'm not in Algebra at the moment so I've yet to learn this. However, I just used some logical thinking and figured out the first one. I'm currently doing the second one, and if I figure it out I'll be sure to give you the answer. Anyway, here is how I did the first one. Starting problem: 1/C + 1/3C = 2/3 1/C(1/1 + 1/3) = 2/3 Factor out the 1/C (Distributive Property) (1/1 + 1/3) = 2C/3 Multiply both sides by 'C' to try and isolate 'C'. 3(1/1 + 1/3) = 2C Multiply both sides by '3' 3/1 + 3/3 = 2C Distributive property to simplify 3 + 1 = 2C Simplify 4 = 2C Simplify 2 = C Isolate 'C' I'll try and get the other one later. Hope I've helped.

05-20-2008, 03:24 AM	#5 (permalink)
ARandomGuy Ride em’ Yoshi Join Date: Apr 2008 Posts: 179 Reputation: 27	((y^2)-2)/((y^2)-16)=(y-2)/(y-4) Factor the (y^2)-16 into (y-4)(y+4), then cancel the y+4 with the other y+4 on the other side of the equation. Cross multiply to get: (y+4)(y-2)=(y^2)-2 Multiply the (y+4)(y-2) to get ((y^2)+2y-8)=(y^2)-2 The two y^2 cancels each other out. 2y-8=-2, add the 8 on to the other side to get: 2y=6, divide by 2, y=3

05-20-2008, 03:27 AM	#7 (permalink)
Piggy-Bank Norrin Radd's Nerd Rage Join Date: May 2006 Posts: 1,615 Reputation: 30	Dang. I was too slow. I also got the second one. Ask if you need me to explain it. @PugsPwn: What are you talking about? The answer is correct. Plug it into the equation again and you'll end up with -7/7 = -1/1

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