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Old 05-22-2008, 01:05 AM   #1 (permalink)
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Default Triginomotry problem please. (really easy one)

Ok, So there's a right triangle,

angle of it is 64 degrees
Adjacent leg is X
opposite leg is Y
Hypotunuse is 18

Can anyone help me solve this?
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Old 05-22-2008, 01:10 AM   #2 (permalink)
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The only thing I remember is a2+b2=c2

So just uhm....find the square root of that
and yeah. i don't remember anything else
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Old 05-22-2008, 01:13 AM   #3 (permalink)
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I hope you've been taught this accronym.

SOH CAH TOA

Sine - Opposite over Hypotenuse
Cosine - Adjacent over Hypotenuse
Tangent - Opposite over Adjacent

Excess Information:And to tell the truth, well you could set this up as a proportion because each angle corresponds with it's opposite side. Anyways...

Sin64 = opposite leg/18
So 18sin64 = opposite leg

If you can't figure it out from there, may God help you.
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Old 05-22-2008, 01:14 AM   #4 (permalink)
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the Sq root of the hypotenuse is 4.242 if that helps
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Old 05-22-2008, 01:14 AM   #5 (permalink)
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Quote:
Originally Posted by Rendascus View Post
The only thing I remember is a2+b2=c2

So just uhm....find the square root of that
and yeah. i don't remember anything else
The problem with that is he doesn't have a OR b, just c. So that won't work.

I wish I could be more helpful, I was really good at math last year, Almost made a 100 in Algebra II. But our math class is so damn laid back this year I feel like I have forgotten just about everything I used to know. We aren't really pressured into trying and I don't give a shit about math enough to actually take any initiative myself so I just kind of cruise by with a C now.

Useless post is useless... sorry I can't help.
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Old 05-22-2008, 01:15 AM   #6 (permalink)
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You guys are using trig identities, the hard way.

a^2 + b^2 = c^2

That's for losers.

SOH-CAH-TOA is where it's at.

Oh and for the above post, yes the triangle does have a and b. Each leg corresponds.
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Old 05-22-2008, 01:16 AM   #7 (permalink)
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Quote:
Originally Posted by Mr. First Name Basis View Post
I hope you've been taught this accronym.

SOH CAH TOA

Sine - Opposite over Hypotenuse
Cosine - Adjacent over Hypotenuse
Tangent - Opposite over Adjacent

Excess Information:And to tell the truth, well you could set this up as a proportion because each angle corresponds with it's opposite side. Anyways...

Sin64 = opposite leg/18
So 18sin64 = opposite leg

If you can't figure it out from there, may God help you.
what this guy said.
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Old 05-22-2008, 01:19 AM   #8 (permalink)
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Isn't this cosine law because he has all 3 angles.

See, 90+64-180= 26

So thats the other side.

And with 3 angles you do cosine, or sine law. I forgot which one.

Doesn't matter.. it's easy from there.

If you STILL can't figure it out from there that's sad, and I guess I'll just answer it for you...

Actually I drew it, and it looks like you can do simple sohcahtoa....

Last edited by Sylce; 05-22-2008 at 01:21 AM.
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Old 05-22-2008, 01:20 AM   #9 (permalink)
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Can you use the trigonometry table with the sin cos and tg values?
If you can it's easy...
All you need to do is sin64 = y/hipotenuse
It is 0,898794 = y/18
y = 0,898794 x 18
y = 16,178292

And to find x you just do cos64 = x/hipotenuse
0,438371 = x/18
x = 0,438371 x 18
x = 7,890678

If you can't use the trigonometry table then I have to think more...

Hope I helped you...
(:


Post above...
To do a cosine law you usually need 2 sides and 1 angle..
But it's not neccessary at all..
It's a triangle with a 90 degrees angle...
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Last edited by Seventeen; 05-22-2008 at 01:25 AM.
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Old 05-22-2008, 01:20 AM   #10 (permalink)
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Quote:
Originally Posted by Mr. First Name Basis View Post
You guys are using trig identities, the hard way.

a^2 + b^2 = c^2

That's for losers.

SOH-CAH-TOA is where it's at.

Oh and for the above post, yes the triangle does have a and b. Each leg corresponds.
He doesn't have the values for a and b though.
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