I am having trouble adding and subtracting fractions.

can someone tell me how to do the following...

1/x-2 + 2/x+4 + 1/x-1


x-1/x^2+5x+6 - x-4/x^2-9


...Thanks.

No. Go away.

L-O-L.

Are you serious about this...
Get real, this is ONRPG.com not lemmehelpyouwithyourhomework.com

How about cheating?
Use an Alegbra caculator on the web or type in the problem in google, it'll give you an answer hopefully. :\

But..yeah, I am failing school badly, so don't listen to me...¬_¬

L-O-L.

Are you serious about this...
Get real, this is ONRPG.com not lemmehelpyouwithyourhomework.com

How about cheating?
Use an Alegbra caculator on the web or type in the problem in google, it'll give you an answer hopefully. :\

But..yeah, I am failing school badly, so don't listen to me...¬_¬

then dont post if you can't be helpful, we've had a good share of math related topics here, and many of us are more than capable of solving them.


on topic

chan i'd gladly help, if I could tell wth you typed, on paper no problem, but when math goes on screen i just lose it x-x

then dont post if you can't be helpful, we've had a good share of math related topics here, and many of us are more than capable of solving them.


on topic

chan i'd gladly help, if I could tell wth you typed, on paper no problem, but when math goes on screen i just lose it x-x

Your not being helpful, either.
This is probably Honours Alegbra, do oyu even know how to do this?
I do, but I had never had this problem before considering I just started this kind of Alegbra.

Draw it on paint or something, it's too confusing when it's typed when you're using fractions.

I'm not doing this because it's homeowork, it's because I need to study, I've been at this pratice test for over an hour, and I only solved the easy problems

Your not being helpful, either.
This is probably Honours Alegbra, do oyu even know how to do this?
I do, but I had never had this problem before considering I just started this kind of Alegbra.

honors algebry? that looks like algebra one, and I sure as hell was more helpful than you were, kid.

Telling someone to **** off because their topic is not pertinent to the general title of the site is not considered help, it's what we call ignorance.

He posted this in General Section and not in the Maple section for a reason, and that's because general section has room for all forms of topics as long as they are pertinent, informative, meant for discussion or for asking for help.

Think about your posts and who you're messing with before you start something you won't get out of easily, chum.


Chan, do what zelst said and put this up on paint and I'll help you, I get lost easily with how it's typed.

(1/x-2 + 2/x+4) + 1/x-1

=x+4/2x-4 + 1/x-1

=

Oh man! I forgot how to solve it afterwards.. My Algebra is fck up! I also failed 6 times on Algebra inspite of our inherited genes on being good at math. T T I always thought it was because I didn't always go on school that is why I failed T T oh, well let it be handled by the Math Wiz...

http://img145.imageshack.us/img145/2038/mathhu4.jpg

I'm in honours algebra 1.

**** SCRATCH THAT....

I will upload the correct answer here in a bit. I'll scan it.

I thought you couldn't cross multiply with subtractions?

I thought you couldn't cross multiply with subtractions?

I'm sorry! That made me crack up.

You're going in my sig!

chan i'd gladly help, if I could tell wth you typed, on paper no problem, but when math goes on screen i just lose it x-x

Dude, you too? I could probably help. But, really, I can't tell what the shit you wrote. O_o

Hmm i was never taught how to do this with fractions in school, I'm curious on how to solve this.

Im pretty sure this is it, after going over my math book :p

http://img184.imageshack.us/img184/5891/img001kr5.jpg

edit: You're now my favorite mod sandman
Thanks to you, I probally will get my grade back up, after 3 failed tests. I love onrpg.

(1/x-2 + 2/x+4) + 1/x-1

First find a common denominator for the part in parentheses.

x+4/(x-2)(x+4) + 2(x-2)/(x+4)(x-2), and you get;

x+4/(x²+2x-8) + 2x-4/(x²+2x-8), and then you get;

x+4+2x-4/(x²+2x-8) or;

3x/(x²+2x-8)

Then you find the common denominator between that and the third part and get;

3x(x-1)/(x²+2x-8)(x-1) + (x²+2x-8)/(x²+2x-8)(x-1), simplified to;

3x²-3x/(x³-x²+2x²-2x-8x+8) + (x²+2x-8)/(x³-x²+2x²-2x-8x+8), simplified to;

(3x²-3x+x²+2x-8)/(x³+x²-10x+8), simplified again to;

(4x²-x-8)/(x³+x²-10x+8)


That's how you simplify it. If you're solving for x, I don't recall it being possible with just that information given. You only have one side of an equation.

I love you too, waffles. You are both saviors.

edit: sandman, how did that x+3 suddenly come back alive?

or did you just combine them into one? i think i get it now.

No problem. It's easier to think about a general rule when adding and subtracting fractions when dealing with complex numbers involving variables. For example;

If you're trying to add 1/2 and 1/3, what would you do?

3(1)/3(2) + 2(1)/3(2)

Same rule applies here, it just is a lot more complicated because of the variables.


By the way, what is honors algebra one? We don't have honors Algebra here, so I am curious as to what grade level it is. Like, what would you take before it and after it?

No problem. It's easier to think about a general rule when adding and subtracting fractions when dealing with complex numbers involving variables. For example;

If you're trying to add 1/2 and 1/3, what would you do?

3(1)/3(2) + 2(1)/3(2)

Same rule applies here, it just is a lot more complicated because of the variables.


By the way, what is honors algebra one? We don't have honors Algebra here, so I am curious as to what grade level it is. Like, what would you take before it and after it?

AP courses give you college credit, and tend to be more rigorous than your standard highschool courses.

So you're saying Honors Algebra = AP Algebra? I didn't even know AP Algebra existed. We only have AP Calc.

Im in 8th grade.
Middle school.

one more question /gen/? please? How do you solve for a number..

Oh, say...

2/e-2 - 4/e-1 = 0

If you mean solve for what 'e' equals, you can't with that statement. You only have one side of an equation. All you can do with that is simplify. Without showing my work I believe that would simplify to;

-2(e-3)/(e-2)(e-1)

Something like that.


If you had 2/(e-2)=4/(e-1), then you could solve and get a number value for 'e' because you have both sides of the equation.

oh, I forgot to add "= 0" after that.

come on guys! I believe in you! I'm not going to sleep till I finish this last study problem

EDIT: never mind :3 I found out myself. Thanks onrpg! good night sweet dreams and have an incredibly fun one!

I just insert a random number, then solve it from there. I'm sure there's some formula or some shit, but most of the time I start off guessing when it comes to shit like this.


e = 2

y/n?

wait, it's not 2, D:<.

I just noticed the "-", and forgot i have to reverse the positive 1 to a negative. making the answer -2.
so
so i don't know the answer. D:>

Oh yeah? I'll try guessing.

Oh yeah? I'll try guessing.

NO!!!

e in algebra stands for.... something that has to do with logarithms.

No math book would ever use e as a standard variable.

Just remember that for addition and subtraction of fractions, you need to make them have the same denominator, which is the value on the bottom of the line and when you do something to the denominator, you have to do the same to the numerator, which is the value on top of the line.

e = 2.718281828459045235360287471352

So that is why you should never use 'e' in a algebraic equation!!!

Edit:
I was bored, so I made the first two problem look cleaner...

http://i31.photobucket.com/albums/c398/SURVIVALsp13/problem2.jpg

http://i31.photobucket.com/albums/c398/SURVIVALsp13/problem1.jpg

I remember taking Algebra 1, in the 7th grade. There was no such thing as honors in middle school. Yeah, I'm taking Calc 1 and 2 next year. :)