Ok, So there's a right triangle,
angle of it is 64 degrees
Adjacent leg is X
opposite leg is Y
Hypotunuse is 18
Can anyone help me solve this?
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Ok, So there's a right triangle,
angle of it is 64 degrees
Adjacent leg is X
opposite leg is Y
Hypotunuse is 18
Can anyone help me solve this?
The only thing I remember is a2+b2=c2
So just uhm....find the square root of that
and yeah. i don't remember anything else
I hope you've been taught this accronym.
SOH CAH TOA
Sine - Opposite over Hypotenuse
Cosine - Adjacent over Hypotenuse
Tangent - Opposite over Adjacent
Excess Information:And to tell the truth, well you could set this up as a proportion because each angle corresponds with it's opposite side. Anyways...
Sin64 = opposite leg/18
So 18sin64 = opposite leg
If you can't figure it out from there, may God help you.
the Sq root of the hypotenuse is 4.242 if that helps
The problem with that is he doesn't have a OR b, just c. So that won't work.Quote:
Originally Posted by Rendascus
I wish I could be more helpful, I was really good at math last year, Almost made a 100 in Algebra II. But our math class is so damn laid back this year I feel like I have forgotten just about everything I used to know. We aren't really pressured into trying and I don't give a shit about math enough to actually take any initiative myself so I just kind of cruise by with a C now.
Useless post is useless... sorry I can't help.
You guys are using trig identities, the hard way.
a^2 + b^2 = c^2
That's for losers.
SOH-CAH-TOA is where it's at.
Oh and for the above post, yes the triangle does have a and b. Each leg corresponds.
what this guy said.Quote:
Originally Posted by Mr. First Name Basis
Isn't this cosine law because he has all 3 angles.
See, 90+64-180= 26
So thats the other side.
And with 3 angles you do cosine, or sine law. I forgot which one.
Doesn't matter.. it's easy from there.
If you STILL can't figure it out from there that's sad, and I guess I'll just answer it for you...
Actually I drew it, and it looks like you can do simple sohcahtoa....
Can you use the trigonometry table with the sin cos and tg values?
If you can it's easy...
All you need to do is sin64 = y/hipotenuse
It is 0,898794 = y/18
y = 0,898794 x 18
y = 16,178292
And to find x you just do cos64 = x/hipotenuse
0,438371 = x/18
x = 0,438371 x 18
x = 7,890678
If you can't use the trigonometry table then I have to think more...
Hope I helped you...
(:
Post above...
To do a cosine law you usually need 2 sides and 1 angle..
But it's not neccessary at all..
It's a triangle with a 90 degrees angle...
He doesn't have the values for a and b though.Quote:
Originally Posted by Mr. First Name Basis
I remember Soh Cah Toa, remember it too good, because my friend was saying it like it was desu.
But how? I only know Sine, Cosine, and tangent. I don't want to get too far, I don't even understand how to find the sides with those three things, or what they do.
Edit: OH OH OH OHO HOHOHOHO I GOT IT THANKS GUyZ LOL
Side y is about 16 right?